How do you find the slope and y intercept of $x + 3 y = 12$ $x + 3y = 12$ ?

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Answer 1 · 2015-05-24T23:04:50

Subtract $x$ $x$ from both sides to get:

$3 y = - x + 12$ $3y=-x+12$

Divide both sides by $3$ $3$ to get:

$y = (- \frac{1}{3}) x + 4$ $y = (-1/3)x+4$

This is of the standard slope intercept form $y = m x + c$ $y = mx+c$ with slope $m = - \frac{1}{3}$ $m=-1/3$ and intercept $c = 4$ $c = 4$ .

How do you find the slope and y intercept of x + 3y = 12x+3y=12x + 3y = 12?