How do you find the slope and y intercept of $x+y=7$ ?

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Answer 1 · 2016-01-11T21:46:55

slope = - 1
y-intercept = 7

one form of the equation of a straight line is y = mx + c where m =slope and c is the y-intercept.

rearranging the equation x + y = 7 into this form gives :

y = - x + 7

comparing the 2 equations we see that m = - 1 and c = 7

here is the graph of y = - x +7

graph{-x+7 [-20, 20, -10, 10]}

Answer 2 · 2016-01-11T21:48:38

Slope $=-1$
Y-intercept $=7$

Start with the equation $x+y=7$ .
Subtract $x$ from both sides to get $y=-x+7$ .

The slope is the coefficient of the $x$ term. In this case, it is assumed to be $-1$ because $-x=-1x$ .

The y-intercept is the value of $y$ when $x=0$ . After substituting $0$ for $x$ , we get $y=-0+7$ . This equals $y=7$ , so the y-intercept is $7$ .

How do you find the slope and y intercept of x+y=7x+y=7?