How do you find the slope and y intercept of $y = \frac{5}{4} x + \frac{17}{2}$ $y = 5/4x + 17/2$ ?

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Answer 1 · 2018-04-12T01:16:50

Slope: $\frac{5}{4}$ $5/4$
y-intercept: $\frac{17}{2}$ $17/2$

The equation is written in the form $y = m x + c$ $y=mx+c$ where $m$ $m$ is the slope, and $c$ $c$ is the y-intercept.

$m = \frac{5}{4}$ $m=5/4$

$c = \frac{17}{2}$ $c=17/2$

Answer 2 · 2018-04-12T01:18:16

See a solution process below:

This equation is in slope-intercept form. The slope-intercept form of a linear equation is: $y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

$y = \frac{5}{4} x + \frac{17}{2}$ $y = color(red)(5/4)x + color(blue)(17/2)$

Therefore:

The slope of the line is: $m = \frac{5}{4}$ $color(red)(m = 5/4)$
The $y$ $y$ -intercept is: $b = \frac{17}{2}$ $color(blue)(b = 17/2)$ or $(0, \frac{17}{2})$ $(0, color(blue)(17/2))$

How do you find the slope and y intercept of y = 5/4x + 17/2y=54x+172y = 5/4x + 17/2?