How do you find the slope for (-1,2) and (-5,1)?

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Answer 1 · 2018-03-03T19:47:57

The slope of the line through the points $(- 1, 2)$ $(-1,2)$ and $(- 5, 1)$ $(-5,1)$ is $\frac{1}{4}$ $1/4$ .

Use the slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

A point can be written like this:

$P_{a} = (x_{a}, y_{a})$ $P_a=(x_a, y_a)$

So our two points are:

$P_{1} = (- 1, 2)$ $P_1=(-1,2)$
and
$P_{2} = (- 5, 1)$ $P_2=(-5,1)$

Now plug in out values to the slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

$m = \frac{1 - 2}{- 5 - (- 1)}$ $color(white)m=(1-2)/(-5-(-1))$

$m = \frac{- 1}{- 5 + 1}$ $color(white)m=(-1)/(-5+1)$

$m = \frac{- 1}{- 4}$ $color(white)m=(-1)/(-4)$

$m = \frac{1}{4}$ $color(white)m=1/4$

The slope of the line is $\frac{1}{4}$ $1/4$ .