How do you find the slope for 2x + 3y = 12?

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How do you find the slope for 2x + 3y = 12?

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Answer 1 · 2015-09-11T02:56:21

The slope is $- \frac{2}{3}$ $-2/3$ .
Convert the given equation to the slope-intercept form by solving for $y$ $y$ .

Explanation:

$2 x + 3 y = 12$ $2x+3y=12$ is the standard form for a linear equation. To determine the slope, solve the equation for $y$ $y$ in order to convert to the slope-intercept form $y = m x + b$ $y=mx+b$ , where $m$ $m$ is the slope and $b$ $b$ is the y-intercept.

$2 x + 3 y = 12$ $2x+3y=12$

Subtract $2 x$ $2x$ from both sides.

$3 y = - 2 x + 12$ $3y=-2x+12$

Divide both sides by $3$ $3$ .

$y = - \frac{2}{3} x + \frac{12}{3}$ $y=-2/3x+12/3$ $=$ $=$

$y = - \frac{2}{3} x + 4$ $y=-2/3x+4$

The slope is $- \frac{2}{3}$ $-2/3$

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How do you find the slope for 2x + 3y = 12?

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