How do you find the slope of a line with $x$ $x$ -intercept $3$ $3$ and $y$ $y$ -intercept $- 4$ $-4$ ?

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How do you find the slope of a line with $x$ $x$ -intercept $3$ $3$ and $y$ $y$ -intercept $- 4$ $-4$ ?

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Answer 1 · 2018-07-19T01:35:36

The slope is $\frac{4}{3}$ $4/3$ .

Explanation:

An $x$ $x$ -intercept is the value of $x$ $x$ when $y = 0$ $y = 0$ , so an $x$ $x$ -intercept of $3$ $3$ can be written as a coordinate on the graph as $(3, 0)$ $(3, 0)$ .

Likewise, an $y$ $y$ -intercept is the value of $y$ $y$ when $x = 0$ $x = 0$ , so an $y$ $y$ -intercept of $- 4$ $-4$ can be written as a coordinate on the graph as $(0, - 4)$ $(0, -4)$

Now we have two points, $(3, 0)$ $(3, 0)$ and $(0, - 4)$ $(0, -4)$ .

To find the slope given two points, we use the formula $\frac{rise}{run}$ $"rise"/"run"$ , or $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$ .

Plug in the given points into the formula:
$\frac{- 4 - 0}{0 - 3} = - \frac{4}{- 3} = \frac{4}{3}$ $(-4-0)/(0-3) = -4/-3 = 4/3$

Therefore, the slope is $\frac{4}{3}$ $4/3$ .

Hope this helps!

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