How do you find the slope given (11, -2) and (2, -2)?

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Answer 1 · 2018-04-19T16:02:37

See below..

Slope of a line $m$ passing through $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$" "m=(y_2-y_1)/(x_2-x_1)$

Plugging in the given values we get

$" "m=(11-2)/(-2+2)$

which is undefined, and this gives rise to a special case. The line with undefined slope is a line parallel to the $y$ -axis.

Also, slope is $tan theta$ . When $tan theta=$ undefined, then $theta=pi/2$ , which is parallel to $y$ -axis.

Answer 2 · 2018-04-19T16:33:54

Nothing, undefined, or $0$

We can find the slope or gradient using:

$(Deltay)/(Deltax)$ Where $Delta$ means the 'change in...'

Remembering the coordinates are $(x,y)$

$11 -> 2$ we have to $-9$

$-2 -> -2$ we do nothing.

Therefore using $(Deltay)/(Deltax)$ -> $0/-9$ -> which is nothing, or undefined.

As dividing by $0$ , or multiplying by $0$ gives nothing.