How do you find the slope given $3y= x -1/2$ ?

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Answer 1 · 2017-09-06T12:20:43

See a solution process below:

First, we can put the equation into slope-intercept form. The slope-intercept form of a linear equation is: $y = color(red)(m)x + color(blue)(b)$

Where $color(red)(m)$ is the slope and $color(blue)(b)$ is the y-intercept value.

$3y = x - 1/2$

$(3y)/color(red)(3) = (x - 1/2)/color(red)(3)$

$(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) = x/color(red)(3) - (1/2)/color(red)(3)$

$y = x/3 - 1/6$

$y = color(red)(1/3)x - color(blue)(1/6)$

Therefore, the slope of the line represented by this equation is:

$color(red)(m = 1/3)$

How do you find the slope given 3y= x -1/23y= x -1/2?