How do you find the slope given $y = 3$ $y=3$ ?

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Answer 1 · 2018-03-26T08:32:39

Slope is $0$ $0$ ,

Slope of a line in the form of $y = m x + b$ $y=mx+b$ is $m$ $m$ , and is found by,

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

We have the equation $y = 3$ $y=3$ , which means that the $y$ $y$ value is constant, and so,

$m = \frac{3 - 3}{x_{2} - x_{1}}$ $m=(3-3)/(x_2-x_1)$

$= \frac{0}{x_{2} - x_{1}}$ $=0/(x_2-x_1)$

$= 0$ $=0$

So, the slope is $0$ $0$ .

graph{y=0x+3 [-10, 10, -5, 5]}

As you can see here, there is no change in $y$ $y$ from $x$ $x$ , and so no slope exists.

How do you find the slope given y=3y=3y=3?