Question

How do you find the slope intercept form of the equation of the line that passes through (-1, 5) and is parallel to `4x+2y=8`?

Answer 1

The equation of the line in slope intercept form is `y=-2x+3`.

Explanation:

The slope of the line `4x+2y=8 or 2y= -4x+8 or y= -2x+4` is `-2`(obtained by comparing with the standard form of equation `y=mx+c`)

Parallel lines have same slope .

Thus line passing through `(-1,5)` , parallal to the line `y= -2x+4` has slope `m=-2`

So the equation of the line in slope intercept form is `y=-2x+c`

The point `(-1,5)` is on the line , so it satisfies the equation `y=-2x+c :. 5 = -2* -1 + c or c=5-2=3`.
Hence the equation of the line is `y=-2x+3`. [Ans]