How do you find the slope of $(- \frac{1}{2}, \frac{4}{7}), (8, \frac{4}{7})$ $(-1/2, 4/7), (8, 4/7)$ ?

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How do you find the slope of $(- \frac{1}{2}, \frac{4}{7}), (8, \frac{4}{7})$ $(-1/2, 4/7), (8, 4/7)$ ?

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Answer 1 · 2017-01-10T21:49:30

Because both $y$ $y$ values are the same, $\frac{4}{7}$ $4/7$ , we know this is a horizontal line ( $x$ $x$ can be any value and $y$ $y$ is always $\frac{4}{7}$ $4/7$ .

A horizontal line always has a slope of $0$ $color(red)(0)$

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How do you find the slope of $(- \frac{1}{2}, \frac{4}{7}), (8, \frac{4}{7})$ $(-1/2, 4/7), (8, 4/7)$ ?

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Explanation:

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How do you find the slope of (-1/2, 4/7), (8, 4/7)(−12,47),(8,47)(-1/2, 4/7), (8, 4/7)?

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How do you find the slope of $(- \frac{1}{2}, \frac{4}{7}), (8, \frac{4}{7})$ $(-1/2, 4/7), (8, 4/7)$ ?