How do you find the slope of (-1, -5) and (-4, -5)?

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How do you find the slope of (-1, -5) and (-4, -5)?

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Answer 1 · 2018-03-04T17:43:00

See a solution process below:

Explanation:

The slope can be found by using the formula: $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))$

Where $m$ $m$ is the slope and ( $x_{1}, y_{1}$ $color(blue)(x_1, y_1)$ ) and ( $x_{2}, y_{2}$ $color(red)(x_2, y_2)$ ) are the two points on the line.

Substituting the values from the points in the problem gives:

$m = \frac{- 5 - - 5}{- 4 - - 1} = \frac{- 5 + 5}{- 4 + 1} = \frac{0}{- 3} = 0$ $m = (color(red)(-5) - color(blue)(-5))/(color(red)(-4) - color(blue)(-1)) = (color(red)(-5) + color(blue)(5))/(color(red)(-4) + color(blue)(1)) = 0/-3 = 0$

A line with a slope of $0$ $0$ is, by definition, a horizontal line.

This can be seen in this problem because the $y$ $y$ value for both points are the same: $- 5$ $-5$

Answer 2 · 2018-03-04T18:02:46

$m = 0$ $m=0$

Explanation:

If line passing through two different points $A (x_{1}, y_{1}) and B (x_{2}, y_{2}), t h e n$ $A(x_1,y_1)andB(x_2,y_2), then$ ,slop of $l$ $l$ is
$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $color(red)(m=(y_2-y_1)/(x_2-x_1))$ ,where, $x_{1} \neq x_{2}$ $x_1!=x_2$ .
Here, $A (- 1, - 5), and B (- 4, - 5)$ $A(-1,-5),andB(-4,-5)$
$m = \frac{(- 5) - (- 5)}{(- 4) - (- 1)} = \frac{0}{- 3} = 0$ $m=((-5)-(-5))/((-4)-(-1))=0/-3=0$
Note: $y_{1} = y_{2} \Rightarrow l$ $y_1=y_2rArrl$ ,is passing through y=-5,and $l$ $l$ is // to $X -$ $X-$ axis.So, the slop of $l, i s$ $l,is$ .0

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How do you find the slope of (-1, -5) and (-4, -5)?

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Explanation:

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