How do you find the slope of (2, -1), (-8, -2) (2,1),(8,2)?

2 Answers
May 22, 2017

The slope of the line passing through (2,-1) and (-8,-2)(2,1)and(8,2) is 1/10110

Explanation:

The slope of the line passing through (2,-1) and (-8,-2)(2,1)and(8,2) is

m= (y_2-y_1)/(x_2-x_1)= (-2+1)/(-8-2)=(-1)/-10=1/10m=y2y1x2x1=2+182=110=110 {Ans]

May 22, 2017

"slope "=1/10slope =110

Explanation:

"to calculate the slope use the "color(blue)"gradient formula"to calculate the slope use the gradient formula

color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))
where m represents the slope and (x_1,y_1),(x_2,y_2)" 2 coordinate points"

"the points are " (x_1,y_1)=(2,-1),(x_2y_2)=(-8,-2)

rArrm=(-2-(-1))/(-8-2)=(-1)/(-10)=1/10