How do you find the slope of (2.78,10) and (3.05,12)?

1 Answer
May 26, 2015

Given two points (x_0, y_0)(x0,y0) and (x_1, y_1)(x1,y1), the slope of a line through them is (change in yy) / (change in xx).

That is:

slope = (y_1 - y_0) / (x_1 - x_0)y1y0x1x0

In your case we have x_0 = 2.78x0=2.78, y_0 = 10y0=10, x_1 = 3.05x1=3.05 and y_1 = 12y1=12.

So slope = (12 - 10) / (3.05 - 2.78)12103.052.78

= 2/0.27 = 200/27 = 7.dot(4)0dot(7)=20.27=20027=7..40.7