How do you find the slope of $(5 \frac{1}{2}, - 7 \frac{1}{2})$ $(5 1/2, -7 1/2)$ and $(5 \frac{1}{2}, - 1 \frac{1}{2})$ $(5 1/2, -1 1/2)$ ?

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How do you find the slope of $(5 \frac{1}{2}, - 7 \frac{1}{2})$ $(5 1/2, -7 1/2)$ and $(5 \frac{1}{2}, - 1 \frac{1}{2})$ $(5 1/2, -1 1/2)$ ?

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Answer 1 · 2017-01-07T16:03:26

Because both points have the same $x$ $x$ value ( $5 \frac{1}{2}$ $5 1/2$ ) this is a vertical line parallel to the $y$ $y$ axis. Therefore its slope is undefined.

http://www.themathpage.com/aprecalc/slope-of-a-line.htm#horizontal

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How do you find the slope of $(5 \frac{1}{2}, - 7 \frac{1}{2})$ $(5 1/2, -7 1/2)$ and $(5 \frac{1}{2}, - 1 \frac{1}{2})$ $(5 1/2, -1 1/2)$ ?

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How do you find the slope of $(5 \frac{1}{2}, - 7 \frac{1}{2})$ $(5 1/2, -7 1/2)$ and $(5 \frac{1}{2}, - 1 \frac{1}{2})$ $(5 1/2, -1 1/2)$ ?