How do you find the slope of $(5, - 9), (3, - 2)$ $(5, -9), (3, -2)$ ?

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Answer 1 · 2016-07-08T20:03:09

$m = - \frac{7}{2}$ $m=-7/2$

$A = (5, - 9); A_{x} = 5; A_{y} = - 9$ $A=(5,-9)" ; "A_x=5" ; "A_y=-9$

$B = (3, - 2); B_{x} = 3; B_{y} = - 2$ $B=(3,-2)" ; "B_x=3" ; "B_y=-2$

$m : slope$ $m:"slope"$

$m = \frac{B_{y} - A_{y}}{B_{x} - A_{x}}$ $m=(B_y-A_y)/(B_x-A_x)$

$m = \frac{- 2 + 9}{3 - 5}$ $m=(-2+9)/(3-5)$

$m = \frac{7}{- 2}$ $m=7/(-2)$

How do you find the slope of (5, -9), (3, -2) (5,−9),(3,−2) (5, -9), (3, -2) ?