How do you find the slope of $(6, 3), (7, - 4)$ $(6, 3), (7, -4)$ ?

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Answer 1 · 2016-10-04T18:29:11

$Slope of line is m=-7$ $"Slope of line is m=-7"$

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$P_{1} = (6, 3)$ $P_1=(6,3)$

$x_{1} = 6; y_{1} = 3$ $x_1=6" ; "y_1=3$

$P_{2} = (7 - 4)$ $P_2=(7-4)$

$x_{2} = 7; y_{2} = - 4$ $x_2=7" ; "y_2=-4$

$m : slope$ $m:"slope"$

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

$m = \frac{- 4 - 3}{7 - 6}$ $m=(-4-3)/(7-6)$

$m = - \frac{7}{1}$ $m=-7/1$

$m = - 7$ $m=-7$

How do you find the slope of (6, 3), (7, -4) (6,3),(7,−4)(6, 3), (7, -4) ?