How do you find the slope of $6x-5y=30$ ?

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Answer 1 · 2016-06-14T06:09:25

$6/5.$

The GeneraI eqn. of a line is $ax+by+c=0, a^2+b^2!=0.$ Its slope is given by $-a/b$ .

Hence, the reqd. of the line $=(-6)/-5=6/5.$

How do you find the slope of 6x-5y=306x-5y=30?