How do you find the slope of a line passing through the points R(12,-7) and S(-6,-4)?

Question

1478 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-02T11:29:09

$S l o p e = - \frac{3}{2}$ $Slope=-3/2$

Line passing through the points are- $R (12 . - 7)$ $R(12.-7)$ and $S (- 6, - 4)$ $S(-6,-4)$ .

$R \equiv (12, - 7) \equiv (x_{1}, y_{1})$ $R ≡(12,-7) ≡ (x_1,y_1)$

$S \equiv (- 6, - 4) \equiv (x_{2}, y_{2})$ $S ≡(-6,-4) ≡ (x_2,y_2)$

$S l o p e = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $Slope = (y_2-y_1)/(x_2-x_1)$

$S l o p e = \frac{- 4 - (- 7)}{- 6 - (- 4)}$ $Slope= (-4-(-7))/(-6-(-4))$

$S l o p e = \frac{- 4 + 7}{- 6 + 4}$ $Slope=(-4+7)/(-6+4)$

$S l o p e = \frac{3}{- 2}$ $Slope=3/-2$

$S l o p e = - \frac{3}{2}$ $Slope=-3/2$