How do you find the slope of a line perpendicular to #5y - 6x = 0#?
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"How do I change #int_0^1int_0^sqrt(1-x^2)int_sqrt(x^2+y^2)^sqrt(2-x^2-y^2)xydzdydx# to cylindrical or spherical coordinates?"
1 Answer
Oct 16, 2016
The gradient of the perpendicular to
Explanation:
First write your equation in the form
In this form m is the gradient of the line and c is the y intercept.
The gradient to the perpendicular is the reciprocal of that of the line and the negative
So the gradient of the line is
