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How do you find the slope of a line perpendicular to the line passing through the given two points (0, 0) and (2, -9)?

1 Answer

sankarankalyanam

Apr 13, 2018

$Slope of perpendicular line m_{p} = - \frac{1}{m} = \frac{9}{2}$ $color(violet)("Slope of perpendicular line "m_p = -1 / m = 9/2$

Explanation:

Slope of the given line $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2 - y_1) / (x_2 - x_1)$

$(x_{1}, y_{1}) = (0, 0), (x_{2}, y_{2}) = (2, - 9)$ $(x_1, y_1) = (0,0), (x_2, y_2) = (2, -9)$

$m = \frac{- 9 - 0}{2 - 0} = - \frac{9}{2}$ $m = (-9-0) / (2-0) = -9/2$

Slope of perpendicular line $m_{p} = - \frac{1}{m} = - \frac{1}{- \frac{2}{9}} = \frac{9}{2}$ $m_p = -1 / m = -1 / (-2/9) = 9/2$

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