How do you find the slope of the line $3x-2y=-8$ ?

Question

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Answer 1 · 2015-04-04T20:39:16

Answer: $3/2$

Solution

Arrange this in the form:

$y = mx + c$

where $m$ is the gradient of the line and $c$ is the y intercept

It goes...
$3x - 2y = -8$

$=> 2y = 3x + 8$

$=> y = 3/2x + 4$

Hence $m = 3/2$

ALTERNATIVELY you would differentiate the equation implicitly:

You have $3x - 2y = -8$ . Differentiate each term you get,

$3 -2(dy)/(dx) = 0$

$=> (dy)/(dx) = 3/2$

$(dy)/(dx)$ is the gradient of the line

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