How do you find the slope of the line $- 3 y - 5 y = 6$ $-3y-5y=6$ ?

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Answer 1 · 2015-08-05T00:50:24

I found: slope $= - \frac{3}{5}$ $=-3/5$

You can write it in slope-intercept form:
$y = m x + c$ $y=mx+c$
where the numerical coefficient $m$ $m$ will be the slope:

rearranging:

$- 3 y - 6 = 5 y$ $-3y-6=5y$

Isolating $y$ $y$ you get:

$y = - \frac{3}{5} x - \frac{6}{5}$ $y=-3/5x-6/5$

so the slope is $- \frac{3}{5}$ $-3/5$

How do you find the slope of the line -3y-5y=6−3y−5y=6-3y-5y=6?