How do you find the slope of the line $4x - 3y = 3$ ?

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Answer 1 · 2015-08-16T13:17:45

slope = $4/3$

It is a straight line equation in general form
ax + by + c = 0

Then its slope is = $(-a)/b$

in your case a = 4 ; b = -3

Hence m = $(- 4) /(-3)$ = $4/3$

How do you find the slope of the line 4x - 3y = 34x - 3y = 3?