How do you find the slope of the line 4x-3y+7=04x−3y+7=0?
1 Answer
Mar 10, 2018
Explanation:
"the equation of a line in "color(blue)"slope-intercept form"the equation of a line in slope-intercept form is.
•color(white)(x)y=mx+b∙xy=mx+b
"where m is the slope and b the y-intercept"where m is the slope and b the y-intercept
"Rearrange "4x-3y+7=0" into this form"Rearrange 4x−3y+7=0 into this form
"subtract 4x from both sides"subtract 4x from both sides
cancel(4x)cancel(-4x)-3y++7=0-4x
rArr-3y+7=-4x
"subtract 7 from both sides"
-3ycancel(+7)cancel(-7)=-4x-7
rArr-3y=-4x-7
"divide all terms by "-3
(cancel(-3) y)/cancel(-3)=(-4)/(-3)x+(-7)/(-3)
rArry=4/3x+7/3larrcolor(blue)"in slope-intercept form"
rArr"slope "=4/3