How do you find the slope of the line 4x-3y+7=04x3y+7=0?

1 Answer
Mar 10, 2018

"slope "=4/3slope =43

Explanation:

"the equation of a line in "color(blue)"slope-intercept form"the equation of a line in slope-intercept form is.

•color(white)(x)y=mx+bxy=mx+b

"where m is the slope and b the y-intercept"where m is the slope and b the y-intercept

"Rearrange "4x-3y+7=0" into this form"Rearrange 4x3y+7=0 into this form

"subtract 4x from both sides"subtract 4x from both sides

cancel(4x)cancel(-4x)-3y++7=0-4x

rArr-3y+7=-4x

"subtract 7 from both sides"

-3ycancel(+7)cancel(-7)=-4x-7

rArr-3y=-4x-7

"divide all terms by "-3

(cancel(-3) y)/cancel(-3)=(-4)/(-3)x+(-7)/(-3)

rArry=4/3x+7/3larrcolor(blue)"in slope-intercept form"

rArr"slope "=4/3