How do you find the slope of the line passing through (6,11), (6,-5)?

1 Answer

\infty

Explanation:

Slope of line passing through the points (6, 11)\equiv(x_1, y_1)(6,11)(x1,y1) & (6, -5)\equiv(x_2, y_2)(6,5)(x2,y2)
=\frac{y_2-y_1}{x_2-x_1}=y2y1x2x1
=\frac{-5-11}{6-6}=51166
=\infty=
The line joining the given points (6, 11)(6,11) & (6, -5)(6,5) is vertical having infinite slope