How do you find the slope of the line passing through the points (0, 5) and (-2, -1)?

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How do you find the slope of the line passing through the points (0, 5) and (-2, -1)?

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Answer 1 · 2016-01-23T21:24:38

$y = 3 x + 5$ $y = 3x + 5$

Explanation:

The equation of line is:
$y = m x + b$ $y = mx + b$
where:
$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{5 - (- 1)}{0 - (- 2)} = \frac{6}{2} = 3$ $m = (y_2-y_1)/(x_2-x_1) = (5 - (-1))/(0 - (-2)) = 6/2 = 3$
Note it is evident that b = 5; Why?

Now we know then: $y = 3 x + b$ $y = 3x + b$
Pick any point say (0,5); $y = 3 (0) + 5; b = 5$ $y = 3(0) + 5; b = 5$

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How do you find the slope of the line passing through the points (0, 5) and (-2, -1)?

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