How do you find the slope of the line passing through the points (-2,5), (6,-3)?

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How do you find the slope of the line passing through the points (-2,5), (6,-3)?

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Answer 1 · 2018-04-04T04:40:56

The slope is $- 1$ $-1$ .
Here's how I did it:

Explanation:

To find the slope of something, we do $\frac{△ y}{△ x}$ $(triangley)/(trianglex)$ , or change in y over change in x, or $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$ .

In your question, you have two points on the line, $(- 2, 5)$ $(-2, 5)$ and $(6, - 3)$ $(6, -3)$ . So we can plug them into the equation above and solve for the slope.

(below, m means slope)
$m = \frac{- 3 - 5}{6 - (- 2)}$ $m = (-3-5)/(6-(-2))$

$m = \frac{- 8}{8}$ $m = (-8)/8$

$m = - 1$ $m = -1$

The slope is $- 1$ $-1$ .

Hope this helps!

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How do you find the slope of the line passing through the points (-2,5), (6,-3)?

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