How do you find the slope of the line passing through the points (-7,3) and (3,8)?

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Answer 1 · 2018-03-26T11:07:23

$1/2$

$m=(y_1-y_2)/(x_1-x_2) or (y_2-y_1)/(x_2-x_1)$
$p_1(-7,3)$
$p_2(3,8)$
$m=(3-8)/(-7-3)=(-5)/(-10)=1/2$

Answer 2 · 2018-03-26T11:07:44

Need to find the change in $x$ and $y$
$Deltax=3--7=10$
$Deltay=8-3=5$

We know that slopes and gradients are merely just the rise over the run or the change in y over the change in x $(Deltay)/(Deltax)=5/10=1/2$

Answer 3 · 2018-03-26T11:09:58

1/2

$m=(y_"2"-y_"1")/(x_"2"-x_"1")$

$m=(3-8)/(-7-3)= (-5)/-10=1/2$

Answer 4 · 2018-03-26T11:27:21

The slope is $1/2$

Slope is defined as the change in y over x- $(Deltay)/(Deltax)$ , or as my math teacher always said:

"The rise over the run"

(You rise vertically=(y-direction) and run horizontally= (x-direction)

This can be written as:

Slope= $(y_2-y_1)/(x_2-x_1)$

Then we just plug in your two points x and y values (which point you decide to allocate to 1 or 2 does not matter)

Slope= $(8-3)/((3)-(-7))=(5/10)=(1/2)$