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How do you find the slope of the line that passes through (-1, 2) and (3, -4)?

1 Answer

Ajay P K. · Stefan V.

Jan 19, 2016

Answer is : $- \frac{6}{4} = - \frac{3}{2}$ $" " -6/4 = -3/2$

Explanation:

The slope of a line between two points $(x_{1}, y_{1})$ $(x_1 , y_1)$ and $(x_{2}, y_{2})$ $(x_2, y_2)$ is defined as

$slope = m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $"slope" = m = (y_2 - y_1)/(x_2 - x_1)$

so, the slope here is

$m = \frac{- 4 - 2}{3 - (- 1)} = - \frac{6}{4} = - \frac{3}{2}$ $m = (-4 - 2)/(3 - (-1)) = -6/4 = -3/2$

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