How do you find the slope of the line that passes through (6,1), (8,-4)?

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Answer 1 · 2017-01-29T01:41:22

The slope of the line containing the points $(6,1)$ and $(8,-4)$ is

$m = (-5)/(2)$

The slope of the line is found using the equation

$m = (y_2-y_1)/(x_2-x_1)$

For the points $(6,1)$ and $(8,-4)$

$x_1 = 6$
$x_2 = 1$
$y_1 = 8$
$y_2 = -4$

$m = (-4-1)/(8-6)$

$m = (-5)/(2)$