How do you find the slope of the line that passes through the points G(-6,-1), H(4,1)?

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Answer 1 · 2016-12-01T17:22:21

The slope is $1/5$

When determining the slope (gradient) you read from left to right on the x-axis

point G has $x=-6$ and point H has $x=4$

So we read form G to H

Let the first point be $G ->(x_1,y_1) = (-6,-1)$
Let the second point be $H->(x_2,y_2)=(4,1)$
Let the gradient be $m$

Slope (gradient) = $m=("change in up or down" ->" y-axis")/("change in along "->" x-axis")$

Reading left to right $m=(y_2-y_1)/(x_2-x_1) = ( 1-(-1))/(4-(-6)) = 2/10 = 1/5$

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Note that $" "-(-"some number") = +"some number"$