How do you find the slope of the line through (3,2) (3,-6)?

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Answer 1 · 2015-08-16T13:13:09

It is a vertical curve. Its slope is $\infty$ $oo$

Since x co-ordinate at both the points are '3'

Its equation is x = 3

It is parallel to y axis. Its slope is $\infty$ $oo$
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When two points are given the formula to calculate slope is -

m = $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2 - y_1)/ (x_2 - x_1)$

$x_{1}$ $x_1$ = 3
$y_{1}$ $y_1$ = 2
$x_{2}$ $x_2$ = 3
$y_{2}$ $y_2$ = -6

m = $\frac{(- 6) - 2}{3 - 3}$ $((-6) - 2)/ (3 -3)$ = $\frac{- 8}{0}$ $(-8)/0$ = $\infty$ $oo$