How do you find the slope of $x+8y=16$ ?

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Answer 1 · 2018-04-29T22:33:34

$=>-1/8$

Rearrange the equation into slope-intercept form:

$x+8y=16$

$8y = -x + 16$

$y = -1/8x + 2$

The form of a line is given as $y = mx+b$ , where $m$ is the slope.

Hence, the slope is $-1/8$

How do you find the slope of x+8y=16x+8y=16?