How do you find the slope of x + y = -3x+y=3?

2 Answers
May 15, 2018

See a solution process below:

Explanation:

The standard form of a linear equation is: color(red)(A)x + color(blue)(B)y = color(green)(C)Ax+By=C

Where, if at all possible, color(red)(A)A, color(blue)(B)B, and color(green)(C)Care integers, and A is non-negative, and, A, B, and C have no common factors other than 1

color(red)(1)x + color(blue)(1)y = color(green)(-3)1x+1y=3

The slope of an equation in standard form is: m = -color(red)(A)/color(blue)(B)m=AB

Substituting the values from the equation in the problem gives the slope as:

m = -color(red)(1)/color(blue)(1) = -1m=11=1

May 15, 2018

"slope" = -1slope=1

Explanation:

Recall equation of a line: y = mx + cy=mx+c

Where;

m -> "slope"mslope

Given;

x + y = -3x+y=3

Making yy the subject formula..

x + y = - 3x+y=3

Subract xx from both sides..

x - x + y = - 3 - xxx+y=3x

0 + y = - 3 - x0+y=3x

y = - 3 - xy=3x

y = -x - 3y=x3

y = -1(x) - 3y=1(x)3

Hence the slope of the equation is -11