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How do you find the slope perpendicular to $x + y = - 3$ $x + y = -3$ ?

1 Answer

Jun 15, 2015

A slope of $1$ $1$ is perpendicular to $x + y = - 3$ $x+y = -3$

Explanation:

If we rewrite $x + y = - 3$ $x+y= -3$ in slope-intercept form, we get

$XXXX$ $color(white)("XXXX")$ $y = (- 1) x - 3$ $y= (-1)x -3$ with a slope of $m = (- 1)$ $m=(-1)$

For any slope $m$ $m$ , the slope perpendicular to it is $(- \frac{1}{m})$ $(-1/m)$

So the slope perpendicular to $x + y = - 3$ $x+y= -3$ is $(- \frac{1}{- 1}) = 1$ $(-1/(-1)) = 1$

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