How do you find the slope that is perpendicular to the line $2 x + y = 6$ $2x + y = 6$ ?

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Answer 1 · 2016-08-13T22:33:50

The slope perpendicular to $m = - 2 is m = + \frac{1}{2}$ $m= -2 " is m " = +1/2$

Change the equation into "slope/intercept" form, $y = m x + c$ $y = mx+c$

$y = - 2 x + 6, m = - 2 and c = 6$ $y = -2x+6, " "m = -2 and c = 6$

The slope perpendicular to $m = - 2 is m = + \frac{1}{2}$ $m= -2 " is " m = +1/2$

For perpendicular lines, one slope is the negative reciprocal of the other.

If $m_{1} = \frac{a}{b} then, m_{2} = - \frac{b}{a}$ $m_1 =a/b " then, " m_2 = -b/a$

How do you find the slope that is perpendicular to the line 2x+y=62x + y = 6 ?