How do you find the slope that is perpendicular to the line $5 x + y = 2$ $5x+y=2$ ?

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Answer 1 · 2016-10-05T01:23:58

$\frac{1}{5}$ $1/5$

A straight line in slope and intercept form is: $y = m x + c$ $y=mx+c$
Where $m$ $m$ is the slope and $c$ $c$ is the intercept on the $y$ $y$ -axis

For two lines to be perpendicular to one another the product of their slopes must $= - 1$ $=-1$

In this example: $y = - 5 x + 2 \to m = - 5$ $y=-5x+2 -> m=-5$

Hence the slope of the line perpendicular $= \frac{- 1}{- 5} = \frac{1}{5}$ $= (-1)/-5 = 1/5$

How do you find the slope that is perpendicular to the line 5x+y=25x+y=25x+y=2?