How do you find the slope that is perpendicular to the line # y = 6x + 2#?

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Answer 1 · 2016-12-24T17:48:36

The slope of a perpendicular line will be #-1/color(red)(6)#

Let the slope of a line be called #color(red)(m)#

The slope of a line perpendicular to this first line will be #-1/m#

The line in this problem is in the slope intercept form:

#y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept.

Therefore, a line perpendicular to the line #y = color(red)(6)x + color(blue)(2)#
will have a slope of:

#-1/color(red)(6)#