How do you find the slope & y-intercept of the equation $3 x + 5 y = 15$ $3x + 5y = 15$ ?

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Answer 1 · 2018-03-24T11:18:25

Slope is $- \frac{3}{5}$ $-3/5$ and y-intercept is $3$ $3$

$3 x + 5 y = 15$ $3x+5y=15$ [Make y as subject]

$:. 5y=-3x+ 15 or y = -3/5x+3$

Comparing with slope intercept form of straight line $y=mx+c$

we find here slope $m= -3/5$ and y-intercept as $c=3$

Therefore , slope is $-3/5$ and y-intercept is $3$

graph{3x+5y=15 [-10, 10, -5, 5]} [Ans]

How do you find the slope & y-intercept of the equation 3x + 5y = 153x+5y=153x + 5y = 15?