How do you find the standard form given #2x^2+4y^2+12x-8y+25=0#?

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How do you find the standard form given #2x^2+4y^2+12x-8y+25=0#?

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Answer 1 · 2017-02-14T03:10:30

This is an invalid equation. It represents an imaginary ellipse, with imaginary semi axes #a = isqrt3 and b = isqrt3/2#.

#isqrt3#.

Explanation:

In the standard form, the equation is

#(2(x+3)^2-18)+(4(y-1)^2=4)+25=0#, giving

#2(x+3)^2+(y-1)^2+3=0#,

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How do you find the standard form given #2x^2+4y^2+12x-8y+25=0#?

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