How do you find the stationary points of the function #y=x^2+6x+1#?

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Answer 1 · 2018-04-10T12:03:02

#(-3,-8)#

The stationary points of a function are when #dy/dx=0#

#y=x^2+6x+1#

#dy/dx=2x+6#

#dy/dx=0=2x+6#

#x=-6/2=-3#

#(-3)^2+6(-3)+1=9-18+1=-8#

Stationary point occurs at #(-3,-8)#