How do you find the sum of the first 25 terms of an arithmetic sequence whose 7th term is −247 and whose 18th term is −49?

1 Answer
Jul 17, 2015

The sum of the first 25 terms is #color(red)(-3475)#.

Explanation:

We know that #a_7 = -247# and #a_18 = -49#.

We also know that #a_n = a_1 + (n-1)d#.

#a_18 = a_1 + (18-1)d#

Equation (1): #-49 = a_1 + 17d#

and

#a_7 = a_1 + (7-1)d#

Equation (2):#-247 = a_1 + 6d#

Subtract Equation (2) from Equation (1).

#-49 + 247 = 17d -6d#

#198 = 11d#

Equation (3): #d= 18#

Substitute Equation (3) in Equation (1).

#-49 = a_1 + 17d#

#-49 = a_1 + 17×18 = a_1 + 306#

#a_1 = -49-306 = -355#

So #a_1 = -355# and #d = 18#.

#a_n = a_1 + (n-1)d#

So the 25th term is given by

#a_25 = -355 + (25-1)×18 = -355 + 24×18 = -355 + 432#

#a_25 = 77#

The sum #S_n# of the first #n# terms of an arithmetic series is given by

#S_n = (n(a_1+a_n))/2#

So

#S_25 = (25(a_1+a_25))/2 = (25(-355+77))/2 = (25(-278))/2#

#S_25 = -3475#