A geometric series of first term #a# and common ratio #r# is divergent if #|r|>=1#, and convergent if #|r|<1#, in which case the sum is given by the formula #a/(1-r)#. In the present case #r=1/6# is less than 1 in absolute value, so that the series is convergent and its sum is #-5/(1-(1/6))=-6#. See Geometric Series