How do you find the sum of the infinite geometric series given #Sigma 40(3/5)^(n-1)# for n=1 to #oo#?
#sum_(n=1)^oo 40(3/5)^(n-1)#
1 Answer
Apr 15, 2018
Explanation:
The sum of an infinite geometric series in the below form is given by
Here, for