Question

How do you find the sum of the series `2n^2+1` from n=0 to 4?

Answer 1

65

Explanation:

Just write out the terms:
`sum_(n=0)^4 2n^2 + 1 = (2(0)^2+1)+(2(1)^2+1)+(2(2)^2+1)+(2(3)^2+1)+(2(4)^2+1)`
`\ \ \ = (0+1) + (2+1)+(8+1)+(18+1)+(32+1)`
`\ \ \ = 60+6`
`\ \ \ = 65`