How do you find the sum of the series 2n^2+12n2+1 from n=0 to 4?

1 Answer
Steve M
Jan 26, 2017

65

Explanation:

Just write out the terms:
sum_(n=0)^4 2n^2 + 1 = (2(0)^2+1)+(2(1)^2+1)+(2(2)^2+1)+(2(3)^2+1)+(2(4)^2+1)4∑n=02n2+1=(2(0)2+1)+(2(1)2+1)+(2(2)2+1)+(2(3)2+1)+(2(4)2+1)
\ \ \ = (0+1) + (2+1)+(8+1)+(18+1)+(32+1)
\ \ \ = 60+6
\ \ \ = 65

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