How do you find the sum of the series i/(i-1)ii−1 from i=2 to 6?

1 Answer
Steve M
Nov 22, 2016

sum_(i=2)^6 i/(i-1) = 437/60 6∑i=2ii−1=43760

Explanation:

As there are only a few terms we could just write them out and compute the sum;
sum_(i=2)^6 i/(i-1) = 2/(2-1) + 3/(3-1) + 4/(4-1) + 5/(5-1) + 6/(6-1) 6∑i=2ii−1=22−1+33−1+44−1+55−1+66−1
:. sum_(i=2)^6 i/(i-1) = 2/1 + 3/2 + 4/3 + 5/4 + 6/5
:. sum_(i=2)^6 i/(i-1) = 437/60

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