Question

How do you find the sum of the series `k^2` from k=1 to 35?

Answer 1

`sum_(k=1)^35 k^2 = 14910`

Explanation:

We need the standard formula `sum_(r=1)^n r^2=1/6n(n+1)(2n+1)`

`:. sum_(k=1)^35 k^2 = 1/6(35)(35+1)(70+1)`
`:. sum_(k=1)^35 k^2 = 1/6(35)(36)(71)`
`:. sum_(k=1)^35 k^2 = 14910`