How do you find the two quadrants that #theta# could terminate given #sintheta=-3/sqrt10#?
1 Answer
May 13, 2017
Explanation:
#"for " 180^@ < theta < 0^@" that is first/second quadrants"#
#"then " sintheta" has a "color(blue)"positive value"#
#"for " 360^@ < theta < 180^@" that is third/fourth quadrants"#
#sintheta" has a "color(blue)"negative value"#
#"since "sintheta=-3/sqrt10#
#"then "theta" will terminate in the third or fourth quadrant"#
#"the acronym " ASTC" indicates which ratio is "color(red)"positive"#
#"in the relevant quadrant"#
#A" indicates All trig ratios in first quadrant"#
#S" indicates Sine ratio in second quadrant"#
#T" indicates Tangent ratio in third quadrant"#
#C" indicates Cosine ratio in fourth quadrant"#