How do you find the unit vector having the same direction as vector $v = –12j$ ?

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Answer 1 · 2016-07-19T11:39:42

$hat(v) = -vec(j)$

$hat(v) = (vec(v))/(|vec(v)|)$

$|vec(v)| = sqrt((-12)^2) = 12$ (this is the norm or length of the vector so we take the positive root.

$hat(v) = (-12vec(j))/12 = -vec(j)$

How do you find the unit vector having the same direction as vector v = –12jv = –12j?